Practice Questions

10. When a vector is resolved into rectangular components the magnitude of the vector is related to its components by

A. (V=V_x+V_y)
B. (V=V_x-V_y)
C. (V=sqrt{V_x^2+V_y^2})
D. (V=V_xV_y)

Perpendicular components obey the Pythagorean relationship.

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(R=sqrt{12^2+5^2}=13) N.

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(V_x=Vcos90^circ=0).

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(tantheta=4/3). Hence (thetaapprox53^circ).

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(F_x=Fcos60^circ=10(0.5)=5) N.

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Equal and opposite vectors cancel. Therefore (R=5-5=0) N.

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4. A displacement of 20 m is directed entirely along the negative x-axis. Its rectangular components are

A. 20 m and 0 m
B. -20 m and 0 m
C. 0 m and -20 m
D. 20 m and 20 m

A vector along the negative x-axis has a negative x-component and zero y-component.

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(V=sqrt{12^2+5^2}=sqrt{169}=13) m.

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(R=sqrt{6^2+8^2}=10) N. The perpendicular components form a right triangle.

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(V_x=Vcos37^circ=10(0.8)=8) N and (V_y=Vsin37^circ=10(0.6)=6) N.

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