Practice Questions

The glycosidic linkage in trehalose, a disaccharide found in insect hemolymph, is an α,α-1,1 linkage between two glucose units. This makes trehalose a non-reducing sugar, a property that is vital for

A. Allowing it to be easily transported across the gut wall without being metabolized during transit
B. Preventing it from reacting with the amino groups of proteins and peptides in the hemolymph
C. Enabling it to be a structural component of the insect exoskeleton
D. Allowing it to function as a signaling molecule in neuronal synapses

A non-reducing sugar lacks a free carbonyl group, so it cannot participate in non-enzymatic glycation (Maillard reaction) with amino groups. This stability is crucial in the hemolymph, where high concentrations of trehalose could otherwise react with and damage circulating proteins.

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Jun 27, 2026

In the plant cell, the site of starch synthesis and storage is the

A. Chloroplast and amyloplast
B. Smooth endoplasmic reticulum
C. Golgi apparatus
D. Mitochondrial matrix

Starch is synthesized in plastids. Transitory starch is synthesized in chloroplasts during photosynthesis and broken down at night. Storage starch is synthesized and stored in amyloplasts (non-pigmented plastids) in tissues like tubers, seeds, and roots.

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Jun 27, 2026

Dextran, a polysaccharide used medically as a plasma volume expander, is composed of glucose units linked primarily by

A. β-1,4 glycosidic bonds
B. α-1,6 glycosidic bonds
C. α-1,4 glycosidic bonds
D. β-1,3 glycosidic bonds

Dextran is a branched bacterial polysaccharide of D-glucose, with a backbone of α-1,6 glycosidic linkages and α-1,3 branch points. Its high molecular weight and colloidal osmotic properties make it useful for drawing fluid into the circulatory system.

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Jun 27, 2026

The physical property of cellulose that makes it an ideal structural molecule is its extreme insolubility in water, a consequence of

A. The highly branched structure that creates a gel-like network
B. Extensive intermolecular hydrogen bonding between adjacent, parallel linear chains
C. The presence of numerous ionic charges along the polymer backbone
D. The formation of covalent cross-links between glucose units

Cellulose's linear, unbranched chains allow them to lie parallel and form extremely stable, regular intermolecular hydrogen bonds. These strong lateral interactions create crystalline microfibrils that exclude water and are highly resistant to hydrolysis.

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Jun 27, 2026

The Osazone test is a chemical test for reducing sugars that involves the reaction of phenylhydrazine with the carbonyl group. In this reaction, glucose and fructose form identical needle-shaped osazone crystals because

A. They are structural isomers that are epimerized under the reaction conditions
B. The reaction only engages the first two carbon atoms, forming the same derivative from both sugars
C. Fructose is first converted to glucose by the phenylhydrazine
D. Both sugars form a furanose ring structure under the reaction conditions

The osazone formation involves C-1 and C-2 of a reducing sugar. Glucose and fructose differ only in the configuration at C-1 and C-2 (glucose is an aldose, fructose is a ketose). The reaction eliminates these differences, forming an identical phenylosazone. The rest of the carbon skeleton is identical.

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Jun 27, 2026

In the context of carbohydrate classification, a triose sugar serves as a critical intermediate in metabolic pathways. The simplest aldose and ketose trioses are, respectively

A. Erythrose and Erythrulose
B. Glyceraldehyde and Dihydroxyacetone
C. Ribose and Ribulose
D. Glucose and Fructose

Trioses are 3-carbon monosaccharides. The simplest aldose (aldehyde-containing) triose is glyceraldehyde. The simplest ketose (ketone-containing) triose is dihydroxyacetone. Both are key intermediates in glycolysis and photosynthesis.

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Jun 27, 2026

Sucrose is commonly known as “invert sugar” after its hydrolysis, because the resulting mixture of glucose and fructose

A. Precipitates out of solution as a solid
B. Changes the direction of plane-polarized light from dextrorotatory to levorotatory
C. Has a higher boiling point than the original sucrose solution
D. Absorbs visible light and becomes colorless

Sucrose is dextrorotatory (+66.5°). Upon hydrolysis, the resulting fructose is strongly levorotatory (-92°), which outweighs the dextrorotation of glucose (+52.7°). The net optical rotation of the mixture (invert sugar) is negative (-19.8°), thus the rotation is inverted.

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Jun 27, 2026

A common intermediate in the metabolic pathways of both starch digestion and cellulose synthesis is

A. Glucose-1-phosphate
B. Fructose-2,6-bisphosphate
C. Ribose-5-phosphate
D. Erythrose-4-phosphate

Starch digestion hydrolyzes starch to glucose, which is then phosphorylated to glucose-6-phosphate and isomerized to glucose-1-phosphate for entry into glycolysis. Cellulose is synthesized in plants from the activated monomer UDP-glucose, which is derived from glucose-1-phosphate.

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Jun 27, 2026

The main reason that the structure of glycogen is more suitable for rapid energy mobilization in animal tissues than starch in plants is its

A. Lower molecular weight, allowing for faster diffusion
B. Higher degree of branching, which provides more non-reducing ends for enzymatic attack
C. Exclusive presence of α-1,4 linkages, which are easier to hydrolyze
D. Association with lipid droplets in the cytoplasm

Glycogen's extreme branching creates a compact, highly soluble granule with thousands of terminal non-reducing ends. Enzymes like glycogen phosphorylase and debranching enzyme can work simultaneously at multiple ends, releasing glucose-1-phosphate far faster than from the less branched amylopectin of starch.

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Jun 27, 2026

The iodine test is a specific qualitative test used to detect the presence of starch. The characteristic blue-black color is a result of the

A. Oxidation of iodine by the aldehyde groups of starch
B. Formation of a covalent bond between iodine and glucose monomers
C. Trapping of polyiodide ions (I₃⁻, I₅⁻) within the helical structure of amylose
D. Reduction of iodine to iodide by the reducing end of amylopectin

Amylose forms a left-handed helix. Iodine (as I₃⁻ or I₅⁻ ions) fits into the central hydrophobic channel of this helix. The resulting charge-transfer complex absorbs light strongly, giving a characteristic deep blue-black color.

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Jun 27, 2026
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